Two 110 kg bumper cars are moving toward each other in opposite directions. car a is moving at 8 m/s and car z at –10 m/s when they collide head–on. if the resulting velocity of car a after the collision is –10 m/s, what is the velocity of car z after the collision?

Explanation:

Mass of bumper cars,

Initial speed of car A,

Initial speed of car Z,

Final speed of car A after the collision,

We need to find the velocity of car Z after the collision. Let it is equal to . Using the conservation of momentum as :

So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer