Answers: 1
![v[/text]= average velocity[tex]t[/text]= time in motionBecause it is a projectile in motion thrown at a 29.4 m/s with an angle of 30°, we need to find the vertical part of that velocity. The vertical part is given by the [tex]sin](/tpl/images/0295/3406/c4a53.png)
of the angle of 30°
average velocity
\\ because the baseball goes the opposite direction when is going down until it gets to the grown. Then 
and we get 
time in motion![v[/text]= average velocity=[tex]14.7\frac{m}{s}](/tpl/images/0295/3406/ebc9b.png)
![t[/text]= time in motion=[tex]1.5s](/tpl/images/0295/3406/5dc35.png)
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Abaseball thrown from the outfield is released from shoulder height at an initial velocity of 29.4 m...
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