You are standing on a ladder, with some repairs at home. you drop a hammer and it hits the floor at a speed of 12 feet per second. if the acceleration due to gravity (
g. is 32 feet/second2, how far above the ground (h) was the hammer when you dropped it? use the formula:

Answer : Height, s = 2.25 ft.

Explanation :

It is given that,

Initial velocity of the hammer, u = 0

Final velocity of the hammer, v = 12 ft/s

Acceleration of the hammer,

From third equation of motion we have :

s is the height.

The hammer is placed 2.25 ft above the ground when it is dropped.

Hence, this is the required solution.

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