What is the angle of refraction of a light ray that enters the surface of a calm lake from air at an angle of 45o to the normal? the refractive index of water is 1.333.

The angle of refraction of a light ray that enters the surface of a calm lake from air can be determined using Snell's Law. This law provides the relationship: 
n1*sinθ1 = n2*sinθ2, where, n1 and n2 refer to the refraction index of the media, and θ1 and θ2 refer to the angle of incidence. In this case n1 (air) = 1.00029, n2 (water) = 1.333, and θ1 = 45°. Using the given values, we obtain θ2 = 32.05°.

Ido not know at all