A5 kg block is pulled across a table by a horizontal force of 40 n with a frictional force 8 n opposing the motion. calculate the acceleration of the object

a=6.4m/s^2

Explanation:

from basic terms , this problem can be tied to newtons second law of motion,

which states that

The rate of change in motion is directly proportional to the force applied .

a force is that which tends to change a body's state of rest or uniform motion in a straight line.

frictional force is the force tat oppose the motion between an object

acceleration is the cane in velocity per time

mass is the composition of matter in an object.

f m(v-u)/t

f=km(v-u)/t

k=1

f=m(v-u)/t

(v-u)/t=a

f=ma

the sum of forces on this block will be

F-Fr=ma

notice that the frictional force is in opposition to the horizontal force, hence it is designated as a negative force

40-8=5a

32=5a

a=32/5

a=6.4m/s^2

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).