Your boss asks you compare two sound waves and determine which has the higher frequency. wave a has a period of 4⁄100 second and wave b has a period of 1⁄7 second. what would you tell your boss?

a. wave b has the higher frequency. its frequency is 7 hz.
b. wave a has the higher frequency. its frequency is 25 hz.
c. wave b has the higher frequency. its frequency is 42 hz.
d. wave a has the higher frequency. its frequency is 4 hz.

Answer

B. Wave A has the higher frequency. Its frequency is 25 Hz.

Explanation

Frequency is the number of oscillation/revolutions in a unit time. On the other hand, period is the time taken to complete one oscillation/revolution.

From the definition above we can conclude that, frequency(f) is the reciprocal of period(T). That is;

f = 1/T and

T = 1/f

Wave A

f = 1/(4/100)

= 100/4

= 25 Hz

Wave B

f = 1/(1/7)

= 7/1

= 7 Hz

So, wave A has the higher frequency. Its frequency is 25 Hz.

The correct answer is Option B.

Explanation:

Frequency is defined as the reciprocal of time period. It is measured in Hertz(Hz) or .

For wave A:

Time period given is . So, frequency will be:

For wave B:

Time period given is . So, frequency will be:

From above, we can say that the frequency of wave A is more than the frequency of wave B.

Hence, the correct answer is Option B.

this is a good question! i'll do some research and come back when i have the answer!

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary