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D=Vi (t)+1/2at^2 solve for d
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Acave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. the lift is performed in three stages, each requiring a vertical distance of 10.0 m: (a) the initially stationary spelunker is accelerated to a speed of 4.90 m/s; (b) he is then lifted at the constant speed of 4.90 m/s; (c) finally he is decelerated to zero speed. how much work is done on the 68.0 kg rescue by the force lifting him during each stage?
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Which changes would result in a decrease in the gravitational force btween two objects? check all that apply
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D=Vi (t)+1/2at^2 solve for d...
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