Acircuit has a current of 2 a. if the resistance in the circuit decreases to one-fourth of its original amount while the voltage remains constant, what will be the resulting current?
0.5 a
2 a
4 a
8 a

The resulting current 8 A.

Explanation:

Current , I = 2A

Voltage applied = V

Resistance offered by the circuit = R

V= IR (Ohm's law)

Now,the resistance in the circuit decreases to one-fourth of its original amount while the voltage remains constant

The new current I' will be given as:

The resulting current will be 8 A when resistance in the circuit decreases to one-fourth of its original amount while the voltage kept constant.

tbh i dont know ether

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