Abaseball has a mass of 0.145 kg and is 12 m above the ground. if it has a mechanical energy of 105.8 j, how fast is it moving?

ME = PE + KE
ME = mgh + 1/2mv^2
105.8 J = (0.145)(9.81)(12m) + (1/2)(0.145)(v^2)<- what you need to solve for
105.8 J = 17.07 + 0.0725v^2
105.8 J - 17.07 = 0.0725v^2
88.73 = 0.0725v^2
88.73/0.0725 = v^2
1223.86 = v^2
√1223.86 = v
34.98 = v or v = 34.98

hope this helps :)

If one were to put the y value into the equation, they could find out what x is for a certain value of y.  putting in the value of y (1), we get the equation: 1=4x-12=4xx=0.5this means that the value of x when why is 1 is x=0.5