Support that p(e)=0.76,p(f)=0.45,and p(e and f)=0.32. what is p (e or f)?

The probability of (E and F) = P(e) times P(f) = 0.76 x 0.45 = 0.342 .

The probability of (e OR f) =

                                   1 - P(not e AND not f) =

                                   1 - P(not e) x P(not f) =

                                   1 - (1 - 0.76) x (1 - 0.32) =

                                   1 - ( 0.24 )   x   ( 0.68 )  =  1 - 0.1632  =  0.8368.

The answers would be: 1: the liquid only contains one compound4: the liquid is a pure substance