How high above the earth's surface is g reduced to 8.80m/^2?

Explanation:

We use the equation to calculate gravitational acceleration

where  is the universal gravitational constant , is the mass of the earth: , and is the radius from the center of earth.

Clearing for the distance r:

substituting known values

and since the radius of earth from the core to the surface is about , the distance above the surface where g is reduce to  is:

wich in kilometers is:

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

need to see circuit to get time constant