"in the diagram below, point p is located in the electric field between two oppositely charged parallel plates.

compared to the magnitude and direction of the electrostatic force on an electron placed at point p, the electrostatic force on a proton placed at point p has
(1)the same magnitude and the same direction
(2)the same magnitude, but the opposite direction
(3)a greater magnitude, but the same direction
(4)a greater magnitude and the opposite direction"

Explanation :

From the given figure, point P is located in the electric field between two oppositely charged parallel plates.

If an electron is placed at point P, it will repel by the negative plate of the capacitor and will move towards positive plate i.e. from the negative plate to positive plate.

Similarly, when a proton is placed at point P, it will attract towards the negative plate i.e. the direction of the proton will be from positive plate to negative plate.

We know that the electrostatic force is inversely proportional to the square of the distance.

So, the electrostatic force on a proton placed at point P has a greater magnitude and the opposite direction".

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j