An alpha particle(the nucleus of a helium atom) has a mass of 6.64*10^-27kg and a charge of +2e. what are the magnitude and direction of the electric field that will balance the gravitational force on it? mp= 1.67*10^-27kg

Magnitude of electric field E= 2.03×10^-7NC^-1

The charge is positive,the electric force is in the same direction as the electric field according to F= qE

Therefore,the direction of the electric field is upward.

Explanation:

Fg=Fe

Where Fe is the force of the electric field

Fg is force of the gravitational field.

Mg= we

Mg= 2eE

E=mg/2e

E= (6.64×10^-27)(9.8)/2(1.6×10^-19)

E=( 6.50×10^-26)/(3.2×10^-19)

E= 2.03×10^-7NC^-1

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: