A0.012kg rubber bullet travels at a velocity of 150m/s, hits a stationary 8.5kg concrete block resting on a frictionless surface, and ricochets in the opposite direction worth a velocity of -100m/s. how fast will the concrete block be moving?

The velocity of concrete block is 0.353 m/s

Explanation:

To calculate the velocity of the concrete block after the collision, we use the equation of law of conservation of momentum, which is:

where,

= mass of rubber bullet = 0.012 kg

= Initial velocity of rubber bullet = 150 m/s

= Final velocity of rubber bullet = -100 m/s

= mass of concrete block = 8.5 kg

= Initial velocity of concrete block = 0 m/s

= Final velocity of concrete block = ?

Putting values in above equation, we get:

Hence, the velocity of concrete block is 0.353 m/s

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