The fast server in women's tennis is venus williams, who recorded a serve of 130 mi/h (209 km/h) in 2007. if her racket pushed on the ball for a distance of 0.15 m, what was the average acceleration of the ball during her serve?

The motion of the ball is an uniformly accelerated motion, so we can use the following equation to find the acceleration:

where

is the final velocity of the ball

is the initial velocity of the ball

is the distance during which the force is applied

is the average acceleration

Rearranging the formula and substituting the numbers, we find:

The average acceleration of the ball during her serve : a = 11232.68 m / s

Regular straight motion is the motion of objects on a straight track that has a fixed speed  

Formula used  

S = distance = m  

v = speed = m / s  

t = time = seconds  

Straight motion changes regularly are the straight motion of objects that have a fixed acceleration  

Formula used  

V = vo + at  

Vt² = vo² + 2aS  

St/S = distance on t  

vo = initial speed  

vt = speed on t  

a = acceleration

The initial speed of the ball when hit = 0

Ball speed = 130 miles / h (209 km / h) = 58.05 m/s

Distance traveled by the ball = 0.15 m then

Vt² = vo² + 2as

58.05² = 0² + 2. a.0.15

3369.8 = 0.3.a

a = 11232.68 m / s

The distance of the elevator

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resultant velocity

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the average velocity

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Keywords:  the average acceleration,fixed acceleration, fixed speed

f=ma newton

f=100x2.5=250n