Physics, 29.08.2019 20:30 desikayla2013

In which environment might you expect a deposit of rock salt or sock gypsum to have formed?
a. deep ocean
b. shallow sea
c. fast moving stream
d. coastline

Answers: 1

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Answer from: kseniyayakimov

Option (B)

Explanation:

Rock salt is commonly known as the halite whose chemical formula is NaCl and gypsums are also soft minerals, forming large colored crystals and are commonly found to be present in association with the rock salt and sulfur deposits. They are also comprised of impurities such as sylvite and sometimes potassium is also found to be present in the form of a mineral. They are formed due to the evaporation of salt water that is mainly made up of dissolved ions namely Na+ and Cl-. They are found mainly in the shallow marginal seas, bays, and estuaries and in the dry lake beds.

Thus, the most likely place for the rock salt and gypsum to occur is the shallow sea.

Hence, the correct answer is option (B).

Answer from: kaleec

Most likely in a shallow sea environment.

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

Answer from: Quest

Initial velocity, u = 4.9 m/sfinal velocity = v m/sinitial height, h₁ = 245 m final height, h₂ = 0a = -9.8 m/s²time taken = t secondss = ut + 0.5at²⇒ (h₂-h₁) = ut + 0.5at²⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get t = 7.59sv = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is 69.48 m/s downward

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In which environment might you expect a deposit of rock salt or sock gypsum to have formed?
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