A4.3 kg bowling ball is initially at rest. if a 15 n force acts on it for 0.85 s, what is the final velocity of the bowling ball?

According to Newton's 2nd law of motion, F = ma ==> a = F / m =15/4.3 = 3.48 m/s^2. Now using kinematic equation, v=u+at => v= 0 + 3.48x0.85 => V= 2.958 m/s