Visible light falls into wavelength ranges of 400-700 nm, for which 1 m = 1 × 10 9 nm . The energy and wavelength of light are related by the equation E = h c λ where E is energy in Joules, h is Planck's constant ( 6.626 × 10 − 34 J-s ), c is the speed of light ( 2.998 × 10 8 m/s ), and λ is the wavelength in m. If a visible light photon has a wavelength of 560.6 nm, what is the energy of the photon (in J)?

E = 3.54 x 10⁻¹⁹ J

Explanation:

The energy of the photon can be given in terms of its wavelength by the use of the following formula:

where,

E = energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ Js

c = speed of light = 2.998 x 10⁸ m/s

λ =  wavelength of light = 560.6 nm = 5.606 x 10⁻⁷ m

Therefore,

E = 3.54 x 10⁻¹⁹ J

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.