A car moves 8 km from home to school and then back to the home. a) Calculate the Distance covered by this car. b) What is the Displacement for the whole trip?

Explanation:

Distance covered = Total distance travelled by the car

Since the car travels to school and back to home again,

Total diatance covered = 8 + 8 = 16km

Displacement = Shortest distance between start point and destination.

Since, the car returns back to home from school,

the start and destination point are same.

So Displacement = 0

they should be similar or the same

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j