Otion 17 A cyclist is moving with a speed of 18km/h on a plane road. He turns the bicycle on the cir
radius 3m. The coefficient of friction between the tyres and road is 0.1. Will he skid or not?​

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a =

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v =

we calculate

      v =

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

momentum of soft ball three times less than baskey ball