On a cold day, the speed of sound in air is 330 m/s. A note with a frequency of 1,320 Hz is played on an instrument. What is the wavelength of that sound wave? 0.25 m 4 m 1,650 m 435,600 m

0.25 m

Explanation:

Given that,

The speed of sound, v = 330 m/s

The frequency of the note of the instrument, f = 1320 Hz

We need to find the wavelength of the sound wave.

We know that,

Wavelength,

Put all the values,

So, the wavelength of the sound wave is equal to 0.25 m.

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see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west