A parallel-plate capacitor is constructed of two disks spaced 2.00 mm apart. It is charged to a potential difference of 500. V. A proton is shot through a small hole in the negative plate with a speed of 2.0 × 105 m/s. What is the farthest distance from the negative plate that the proton reaches?

Explanation:

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton =

a = Acceleration

m = Mass of proton =

Electric field is given by

Force balance is given by

We have the relation

The farthest distance from the negative plate that the proton reaches is .

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e) none of the above answers are correct