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Physics, 10.04.2021 04:30 acofield975

A potential difference of 25.0 V is applied between the ends of a 30.0-m gold wire with a diameter of 5.50 mm. The resistivity of the wire is 2.44 × 10−8 Ω.m. Calculate
the current in the wire,​

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A potential difference of 25.0 V is applied between the ends of a 30.0-m gold wire with a diameter...

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