. Two containers of volumes V 1 and V 2 are connected by a small tube with a valve. Initially, the valve is closed and the two volumes contain monoatomic gas at pressures P 1 and P 2 , and temperature T 1 and T 2 respectively. The initial values are given by: V 1 =24.942 I , P 1 =3.13 bar , T 1 =40^ C , V 2 =49.884 L , P 2 =24.01 bat , T 2 =70^ C . The valve is then opened, and an amount of heat of 111.68 k. J is acquired by the gas. 2. Calculate the final pressure of the gas

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acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27