PLEASE HELP - In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops it in 0.32 min. What average force stops the bullet?​

–0.11 N.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 6.1 g

Initial velocity (u) = 350 m/s

Time (t) = 0.32 mins

Final velocity (v) = 0 m/s

Force (F) =?

Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

0.32 mins = 0.32 × 60 = 19.2 s

Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:

Initial velocity (u) = 350 m/s

Time (t) = 19.2 s

Final velocity (v) = 0 m/s

v = u + at

0 = 350 + (a × 19.2)

0 = 350 + 19.2a

Collect like terms

0 – 350 = 19.2a

–350 = 19.2a

Divide both side by 19.2

a = –350 / 19.2

a = –18.23 m/s²

Next, we shall convert 6.1 g to Kg.

1000 g = 1 Kg

Therefore,

6.1 g = 6.1 g × 1 Kg / 1000 g

6.1 g = 0.0061 Kg

Finally, we shall determine the force. This can be obtained as follow:

Mass (m) = 0.0061 Kg

Acceleration (a) = –18.23 m/s²

Force (F) =?

F = ma

F = 0.0061 × –18.23

F = –0.11 N

NOTE: The negative sign indicates that the force is in opposite direction.

–0.11 N.

Explanation:

Hope this helps