By using kirchhoff's laws, it can be shown that the currents i1, i2, and i3 that pass through the three branches of the circuit in the figure satisfy the given linear system. solve the system to find i1, i2, and i3. (round your answers to three decimal places.)

i(sub)1 + i(sub)2 − i3 = 0
8i(sub)1 − 4i(sub)2 = 2
4i(sub)2 + 2i(sub)3 = 8
r = 8, r2 = 4, r3 = 2
v = 2, v(sub)2 = 8

Solve the second equation for I_1 and the third equation for I_3. Then plug those into the first equation. From here you can solve for I_2. Then you can plug that in to equation 2 to solve for I_1. Then plug in to equation 3 to solve for I_3.

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.