Amass m = 4.6 kg hangs on the end of a massless rope l = 2.16 m long. the pendulum is held horizontal and released from rest.
1)how fast is the mass moving at the bottom of its path? 2)what is the magnitude of the tension in the string at the bottom of the path?

ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.

the rearrangement of particles in a physical change. hope this

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.