A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle?

0.605 m (approx.)

Explanation:

We know, given the radius and the circular velocity we can yield the centripetal acceleration using this equation,

From this equation, we can solve for like this,

the independent variable, or the one that is intentionally manipulated is the speed.

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explanation: