Physics, 25.03.2021 21:40 jasperc2002owy5b5
A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a giant spring at the bottom of the elevator shaft. As the elevator falls, its safety clamp applies a constant frictional force of 17,000 N. 1. List all the forces acting on the elevator after the cable breaks but before it hits the spring. Determine the work done by each force on the elevator. Make sure these work terms have the appropriate signs (positive or negative). 2. Calculate the net work done on the elevator. 3. Use the work-kinetic-energy theorem to determine the speed of the elevator right before it encounters the spring. 4. After the elevator encounters the spring, the spring compresses by 0.6 m before the elevator comes to rest. The safety clamp continues to apply a constant 17,000 N force. List all the forces acting on the elevator while it falls this final 0.6 m. 5. For each force listed in question F4, determine an expression for the work it does on the elevator. Make sure each work term has the appropriate sign (positive or negative). 6. Use the work-kinetic-energy theorem to determine the value of the spring constant k.
Answers: 1
Physics, 22.06.2019 20:50, isarahweller103
Suppose that a mass of 2 kg is attached a spring whose spring constant is 50. the system is damped such that b = 12 . the mass is set in motion with an initial velocity of -8 m/s at a position 0 meters from equilibrium. set up and solve a differential equation that models this motion. write your solution in the form a cos ( ω t − α ) where α is a positive number. use your solution to fill in the information below: what is the amplitude of the motion? what is the value of ω ? what is the phase shift?
Answers: 1
Physics, 22.06.2019 21:50, gshreya2005
Which component is used to measure the current in a circuit? oa. switch ob. resistor oc. ammeter the answer is c. for y’all plato people
Answers: 1
A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a...
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