Physics, 31.01.2020 01:06 nanamath5662

If you plug in your electrical heater in for 15.0 minutes and then in the process used 16,000 j how much power did you use

Answers: 2

Show answers

Answers

Answer from: khynia11

   Power = (energy) / (time)

BUT ... it has to be joules and seconds.

   (15 minutes) x (60 sec/min) = 900 seconds

   Power = (energy) / (time)

   = (16,000 J) / (900 seconds)

   = (16,000 / 900)    joule/sec

   = (17 and 7/9) watts.

That's not much for a 'heater'.

A typical SMALL heater pours out like 1200 watts or 1500 watts.

A company that sells heaters that only put out 17 watts
won't be able to sell many of them, because they're
pretty useless as heaters.

Maybe they could be used as aquarium heaters, or as
hamster-cage heaters.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

Other questions on the subject: Physics

Physics, 21.06.2019 13:30, paulitaaustin

An astronomer at the equator measures the doppler shift of sunlight at sunset. from this, she calculates that earth’s tangential velocity at the equator is 465 m/s. the centripetal acceleration at the equator is 3.41  10 2 m/s 2 . use this data to calculate earth’s radius.

Answers: 3

continue

Physics, 22.06.2019 01:00, hoshoronline8454

When you turn on a battery-operated device, an electrical circuit is

Answers: 1

continue

Physics, 22.06.2019 19:30, FireFlight

Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the length of each side is 1.50 cm . point a is at the center of the square, and point b is at the empty corner closest to q2. take the electric potential to be zero at a distance far from both charges. part a what is the electric potential at point a due to q1 and q2? express your answer with the appropriate units.

Answers: 2

continue

Physics, 23.06.2019 05:10, genesisheaven1

Which of the following should not be included in a great summary? a. blaming your lab partner b. new questions your experiment has generated c. your prediction d. your investigation plan

Answers: 2

continue

You know the right answer?

If you plug in your electrical heater in for 15.0 minutes and then in the process used 16,000 j how...