How much thermal energy is absorbed when 145 g of water at 23ºC is heated until it boils and turns into vapour?

the thermal energy absorbed is 46,893 J

Explanation:

Given;

mass of the water, m = 145 g = 0.145 kg

initial temperature of the water,  t₁ = 23 ⁰C

final temperature of the water, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg.⁰C

The thermal energy absorbed is calculated as;

H = mcΔt

H = 0.145 x 4,200 x (100 - 23)

H = 46,893J

Therefore, the thermal energy absorbed is 46,893J

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

powerful computers now, not then