Abox is sliding along a frictionless surface and gets to a ramp. disregarding friction, how fast should the box be going on the ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (use g = 9.8 m/s2.)

7.0 m/s

From the information;

we have the final velocity, distance, and acceleration,

We therefore, need to find initial velocity;

Using the equation;

vf^2 = vi^2 + 2ad

Making, vi² the subject;

vi² = vf² - 2ad

but; vf is zero because it comes to a stop or rest

Thus; vi² = - 2ad

vI = √(2ad) 

vi= the square root of 2ad

 = √(2×9.8 × 2.5)

vi= 7 m/s

Therefore; initial velocity = 7 m/s

a=d/t

a="triangle"v/t

explanation:

a = acceleration