Just need to confirm an answer A ball of mass 0.2 kg is kicked straight up from ground level. Ignoring air resistance, its gravitational potential energy as it reaches its maximum
height is 10 J. The initial speed with which the ball was kicked is most nearly
(A) 20 m/s (B) 10 m/s (C) 5 m/s (D) 1 m/s

B

Explanation:

Remark

If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.

Formula

KE = 1/2 m v^2

Givens

KE = 10 J

m = 0.2 kg

v = ?

Solution

10 = 1/2 * 0.2 * v^2

10 * 2 = 0.2 * v^2

20 = 0.2 * v^2

20/0.2 = v^2

100 = v^2

v = 10 m/s

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat