3.1. A stone of mass 2kg is thrown vertically upward with a speed of 20m's Calculate the maximum height reached.​

20.41 m

Explanation:

Let's list out the relevant variables in this problem. Take the upwards direction to be positive and the downwards to be negative.

We are using the fact that at maximum height, the object's velocity is 0 m/s right before it changes direction to fall vertically back down to Earth.

Find the constant acceleration equation that contains these four variables.

Substitute the known values into the equation and solve for Δy, the maximum height.

The maximum height of the stone is 20.41 m. Notice that its mass was irrelevant when solving for its maximum height when thrown.

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete