Unpolarized light with an intensity of 42 units is incident on a set of two successive polarizing filters. The polarization axis of the first filter is aligned horizontally, while the axis of the second filter is rotated 32 from the vertical. Determine the intensity of the light after passing through the two filters

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

no simpler subs form complex ones. synthesise = make

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j