32g of water at 60°C is poured into 60g of cold water at 15°C, which is contained in a calorimeter of mass 40g, and S. H.C of water is 0.1Jg'K'. Neglecting heat loss show that
the resulting temperature is 29°C.

Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

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