How much heat is needed to boil 5.30 kg of water at its boiling point? Use Q = mass x latent heat of vaporization.
A. 1760 kJ B. 22.2 kJ C. 530 kJ D. 12,000kJ

Required heat Q = 11,978 KJ

Explanation:

Given:

Mass = 5.3 kg

Latent heat of vaporization of water = 2,260 KJ / KG

Find:

Required heat Q

Computation:

Required heat Q = Mass x Latent heat of vaporization of water

Required heat Q = 5.3 x 2260

Required heat Q = 11,978 KJ

Required heat Q = 12,000 KJ (Approx.)

b.

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