10. A 25 kg apple cart is being pushed with an applied force of 115 N. The coefficient of friction between the ground and the cart is 0.35. What is the acceleration of the cart?

1.1 m/s²

Explanation:

From the question,

F -mgμ = ma Equation 1

Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ =  coefficient of friction., a = acceleration of the apple cart.

Given: F = 115 N, m = 25 kg,  μ  = 0.35

Constant: g = 10 m/s²

Substitute these values into equation 2

115-(25×10×0.35) = 25×a

115-87.5 = 25a

25a = 27.5

a = 27.5/25

a = 1.1 m/s²

im not to sure what it is

the device is called “ rocket engine”