A vertical spring with k = 6900 N/m is compressed 0.060 m. A 0.13 kg ball is placed on top of the spring and released, launching it into the air. How far above the launching point—corresponding to the spring’s free length—is the ball when it has a speed of 2.0 m/s? (Neglect air friction.) Group of answer choices

1.2 m

160 m

19 m

9.5 m

94 m

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: good job it's all correct !

explanation: