The wheel of a certain bus are 2m apart and the bus falls over when it is tilted sideways at 45degree angle with vertical. What is the tension in each rope

F = m g / 4,  F = 12250 N

Explanation:

For this exercise we must use the rotational equilibrium relation

          ∑τ = 0

let's set a reference system on the wheel where the bus is turning and that the anti-clockwise rotations have been positive

          -2F x_string + W x_bus = 0

          x_bus =\frac{l}{2} cos 45

          x_string = l cos 45

where F is the force on each wheel and W the weight of the bus ,, we assume that the center of mass is in the middle and x_bus is the perpendicular distance from the center of mass to the turning point.

             2F l cos 45 = W  cos 45

             F = m g / 4

to finish the calculation we must assume a mass for the bus m = 5000 kg

             F = 5000 9.8 / 4

              F = 12250 N

a long strand of spaghetti is folded once. if this is cut 20 times, how many pieces of spaghetti will there be? a long strand of spaghetti is folded once. if this is cut 20 times, how many pieces of spaghetti will there be? a long strand of spaghetti is folded once. if this is cut 20 times, how many pieces of spaghetti will there be? a long strand of spaghetti is folded once. if this is cut 20 times, how many pieces of spaghetti will there be? a long strand of spaghetti is folded once. if this is cut 20 times, how many pieces of spaghetti will there be?

\

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6