We have a spin-one-half projectile (mass m, Energy E = ℎ
2
2
ଶ
)....
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Physics, 10.03.2021 01:00 zitterkoph
We have a spin-one-half projectile (mass m, Energy E = ℎ
2
2
ଶ
). This projectile scatters
a spin-one-target of infinite mass.
For this, the Hamiltonian is:
∫ = ଵଶ
−
In the above expression, µ > 0, σi represent the Pauli spin operators, where for i=1,
we have the spin operator for projectile and for i=2, we have spin operator for
target.
Evaluate ௗ
ௗΩ
(differential scattering cross section), in lowest order Born
approximation. The same should be calculated as a function of k and scattering
angle. Also, computation should be done averaging over initial; and summing over
final states of spin polarization.
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