A small business operates3 pieces of equipment for 9 hrs continuously per day for 6 days a week if the 3 equipment consume 10kw, 2.5kw and 600watts respectively calculate the weekly cost if charge per unit is 7.9 pence​

5588.46 pence

Explanation:

The following data were obtained from the question:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 600 W

Time (t) = 9 hours per day.

Cost per day = 7.9 pence​ per unit KWh

Cost for a week =?

Next, we shall convert 600 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

600 W = 600 W × 1 KW / 1000 W

600 W = 0.6 KW

Next, we shall determine the total power consumed. This can be obtained as follow:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 0.6 KW

Total power (Pₜ) =?

Pₜ = P₁ + P₂ + P₃

Pₜ = 10 + 2.5 + 0.6

Pₜ = 13.1 KW

Next, we shall determine the total time of operation in a week. This can be obtained as follow:

From the question given above, we were told that:

1 day = 9 hours

Therefore,

6 days = 6 × 9 = 54 hours.

Thus, the total time of operation is 36 hours.

Finally, we shall determine the cost operating the three (3) equipment for a week (i.e 6 days). This can be obtained as follow:

Total power (Pₜ) = 13.1 KW

Total time (tₜ) = 54 hours

Cost per day (Cₔ) = 7.9 pence​ per unit KWh

Cost per week (Cᵥᵥ) =?

Cᵥᵥ = Pₜ × tₜ × Cₔ

Cᵥᵥ = 13.1 × 54 × 7.9

Cᵥᵥ = 5588.46 pence

Therefore, the cost operating the three (3) equipment for a week (i.e 6 days) is 5588.46 pence

a.) is the correct answer.

explanation:

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.