PLEASE HELP! A gas inside a cylinder expands from 5.6 L to 9.2 L at a constant pressure of 3.7 x 10^3 Pa. What work is involved in this process? REMEMBER! You must convert L to m^3.1 L = 0.001 m^3

a) 13,320 J

b) -13.320 J

c) 13.3 J

d) -13.3 J

Explanation:

At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume

ΔV = 9.2 - 5.6 = 3.6 L

3.6 L = 3.6 x 10⁻³ m³

ΔV = 3.6 x 10⁻³ m³

P = 3.7 x 10³ Pa

So work done

= 3.7 x 10³ x 3.6 x 10⁻³ J

= 13.32 J .

( c ) is the answer , because work is done by the gas so it will be positive.

d is the correct answer