The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medium of dielectric constant 7, what will be the value of new coulomb force?

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

Take the ratio of the two forces;

Therefore, the value of new coulomb force is 1.43 N.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge