Agrasshopper can jump a maximum horizontal distance of 40cm. if it spends negligible time on the ground then in this case its speed along horizontal road will be

Considering that the grasshopper starts on the ground and lands on the ground, there is no change in elevation. The range of the grasshopper is given by: R=v2sin2θg If we now take the information that this is a maximal distance, the maximum range is given when the angle of launch is 45 degrees. This yields the equation: Rmax=v2g We know R_max=0.4 m and g=9.8 m/s^2, so we can solve for v: v=1.98m/s We are asked for the horizontal component, which by trigonometry is: vx=vcosθ We again take our angle of launch as 45 degrees and arrive at: vx=1.40m/s

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Inner peace.. jk it's  a stable electron configuration