What is the apparent weight of a 80-kg astronaut 2200 km from the center of the Earth's Moon in a space vehicle moving at constant velocity.

the apparent weight of the astronaut is 81.032 N { towards moon }

Explanation:

Given that;

Mass of astronaut m = 80 kg

Distance of spaceship from the Earth's moon r = 2200 km = 2200 × 10³ m

Acceleration due to gravity of the moon = GM/r²

where M is mass of the moon( 7.34767309 × 10²² kg )

gravitational constant G = 6.67 × 10⁻¹¹

So,

Acceleration due to gravity of the moon g is;

g  = [ (6.67 × 10⁻¹¹) × (7.35 × 10²²) ] / (2200 × 10³)²

g = 4.90245 × 10¹² / 4.84  × 10¹²

g = 1.0129 m/s²

now, we take the positive direction towards the moon if the spacecraft is moving with constant velocity, a = 0

The apparent weight is measured by the normal force FN

so,

∑F = ma

-FN + mg = ma

-FN + mg = 0

FN = mg

we substitute

FN = 80 × 1.0129

FN = 81.032 N { towards moon }

Therefore, the apparent weight of the astronaut is 81.032 N { towards moon }

it consists of the house of representatives and the senate.

explanation:

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it