An Olympic diver is on a diving platform 3.80 m above the water. To start her dive, she runs off of the platform with a speed of 1.24 m/s in the horizontal direction. What is the diver's speed just before she enters the water

the diver's speed just before she enters the water is 8.718 m/s.

Explanation:

Given;

height of the diving platform, h = 3.8 m

initial velocity of the diver, u = 1.24 m/s

the diver's speed just before she enters the water is her final velocity, = v

Apply the following kinematic equation to determine the final velocity of the girl;

v² = u² + 2gh

v² = (1.24)² + 2(9.8 x 3.8)

v² = 76.018

v = √76.018

v = 8.718 m/s

Therefore, the diver's speed just before she enters the water is 8.718 m/s.

idk sorry i only needs point for apex

explanation:

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .