Mr. Voytko wants to know how high in meters he can lift an 0.3 kg apple with 7.35 joules?

the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Explanation:

Given;

energy of Mr. Voytko, E = 7.35 J

mass of the apple, m = 0.3 kg

Apply the principle of conservation of energy.

Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.

E = mgh

where;

h is the height above the ground through Mr. Voytko lifted the apple.

g is acceleration due to gravity = 9.8 m/s²

h = E / (mg)

h = 7.35 / (0.3 x 9.8)

h = 2.5 m

Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

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i just did this and got a 100.

answer: option c.

explanation: