If 59.1 g of pure metal uses 890.9 j of energy to heat it from 26.1 c to 59.6 c, identify the metal

The metal is iron.

Explanation:

We have 59.1 grams of a given metal.

We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C

First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.

ΔT = 59.6°C - 26.1°C = 33.5°C

Now we can find the specific heat, which is calculated as:

c = Ε/(ΔT*m)

Where:

E = energy given to the material = 890.9 J

m = mass of the material = 59.1 gr

ΔT = change in temperature = 33.5°C

Replacing these in the above equation we get:

c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)

Now we need to look at a table of specific heats and see which metal has this specific heat.

We can see that iron is the best match, so we can assume that the metal is iron.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr