Una pelota de golf se suelta desde el reposo del techo de un edificio muy alto. Despreciando la resistencia del aire, calcule (a) la posicion y (b) la velocidad de la pelota despues de 1s, 2s y 3s.

a)   y = y₀ - 4.9, v = -9.8 m / s, b)  y =y₀ - 19.6,  v = - 19 m / s

c)  y =y₀ - 44.1, v = - 29.4 m / s

Explanation:

To solve this exercise let us use the kinematic relations

          y =y₀ + v₀ t - ½ g t²

          v = v₀ - g t

They indicate that the body is released therefore the initial velocity is zero v₀ = 0

          y = y₀ - ½ g t²

          v = - gt

a) the position and velocity for t = 1s

         y = y₀ - ½ 9.8 12

         y = y₀ - 4.9

         v = - 9.8 1

         v = -9.8 m / s

the negative sign indicates that the velocity is directed downwards

b) t = 2 s

         y =y₀ - ½ 9.8 2 2

         y =y₀ - 19.6

         v = - 9.8 2

         v = - 19 m / s

c) t = 3 s

        y = y₀ - ½ 9.8 3 2

        y =y₀ - 44.1

        v = - 9.8 3

        v = - 29.4 m / s

a

explanation:

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e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.